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Topic review

martin

2016-10-10

wolf359 wrote:

I'm having a similar problem. It doesn't seem that this was ever resolved. The strange thing about this error is that neither the GetFiles call nor the catch block is ever hit. I attached all 3 logs. Would you mind taking a look?

The debug log does not seem complete. What error do you get? Or what happens? Does it hang on the Session.Open call? I do not see any relation to this topic. Anyway, please upgrade.

wolf359

2016-10-07 02:02

I'm having a similar problem. It doesn't seem that this was ever resolved. The strange thing about this error is that neither the GetFiles call nor the catch block is ever hit. I attached all 3 logs. Would you mind taking a look?

var options = new SessionOptions
{
Protocol = Protocol.Sftp,
HostName = Settings.Default.remoteHost,
UserName = Settings.Default.username,
SshPrivateKeyPath = Settings.Default.privateKey,
GiveUpSecurityAndAcceptAnySshHostKey = true
};

var session = new Session();
session.FileTransferProgress += Session_FileTransferProgress;
session.FileTransferred += Session_FileTransferred;
session.DebugLogPath = @"C:\data\debug.log";
session.XmlLogPath = @"C:\data\xml.log";
session.SessionLogPath = @"C:\data\session.log";

try
{
session.Open(options);
session.GetFiles(Settings.Default.remoteFolder + title, fileInfo.FullName);
}
catch (Exception e)
{
session.Close();
}

martin

2016-06-27

Not sure what that. What I'm basically asking, if you get the exception at the point it is thrown in the WinSCP code, or if you get it outside of WinSCP code. If the first, you probably have enabled breaking on exception throwing. But most (all) instances of that exception will be handled. So you are not interested in those.

Anyway, this should not occur in 5.8.x anymore.

tmcnairbledsoe

2016-06-23 14:54

I get it from the debug exceptions break list. Not sure if that helps.

martin

2016-06-23

How do you catch that exception?

That cannot be an exception caught outside of the .Open call matching the debug log file.

If you take a look at the WinsCP .NET assembly source code, you will that there's try .. catch block around whole method, where the catch block logs an exception, if any. There's no exception in the log.

tmcnairbledsoe

2016-06-23 14:36

martin

2016-06-23

The .Open succeeded in this case. Did you still get the error? When? When calling the .PutFiles? Can you post a matching callstack and a log file?

WinSCP .NET assembly can be called from multiple threads. But it will block, when used in parallel.

tmcnairbledsoe

2016-06-20 16:47

You got it, good call. I've privately attached the log file. As a side question, can WinSCP handle being used by multiple threads?

martin

2016-06-19

Do you set it to a path to a directory (wrong) or file (correct)?

tmcnairbledsoe

2016-06-15 18:32

Any path I pass in to that property throws an unauthorized access exception. Any advice? This is my local machine so I don't see why this should happen. I am admin.

martin

Re: Cannot access the file '...wscp9D6C.00283D6C.tmp' because it is being used by another process

2016-06-15

Please attach a full debug log file showing the problem (using the latest version of WinSCP).

To generate log file, set Session.DebugLogPath. Submit the log with your post as an attachment. If you do not want to post the log publicly, you can mark the attachment as private.

tmcnairbledsoe

2016-06-14 14:11

Any assistance? This seems like a simple issue that needs to be resolved.

tmcnairbledsoe

Cannot access the file '...wscp9D6C.00283D6C.tmp' because it is being used by another process

2016-06-13 17:00

I have seen this error posted before but there does not seem to be a public resolution to the issue. It occurs when opening a connection. Here is the code and a call stack:

Using session As New Session

                session.Open(sessionOptions)



                Dim transferOptions As New TransferOptions

                transferOptions.TransferMode = TransferMode.Binary



                Parallel.ForEach(imageList, Sub(imagePath)

                                                ProcessWinScp(imagePath, session, transferOptions)

                                            End Sub)

            End Using

Here is where I initialize session options

Dim sessionOptions As New SessionOptions

            With sessionOptions

                .Protocol = Protocol.Ftp

                .HostName = xx

                .UserName = xx

                .Password = xx

            End With