martin wrote:

ssAshkea wrote:

I want to get all the files and folders and put them in a file

Their names/paths or contents? Please be clear!

If paths, this will do:

var filesAndDirectories = session.EnumerateRemoteFiles(directory, null, EnumerationOptions.AllDirectories | EnumerationOptions.EnumerateDirectories);

string list = string.Join(string.Empty, filesAndDirectories.Select(file => file.FullName + Environment.NewLine));

File.WriteAllText(outputFile, list);

ssAshkea wrote:

I want to get all the files and folders and put them in a file

var filesAndDirectories = session.EnumerateRemoteFiles(directory, null, EnumerationOptions.AllDirectories | EnumerationOptions.EnumerateDirectories);

string list = string.Join(string.Empty, filesAndDirectories.Select(file => file.FullName + Environment.NewLine));

File.WriteAllText(outputFile, list);

martin wrote:

ssAshkea wrote:

1) all the files put in the list of recursive?

I do not understand.

ssAshkea wrote:

1) all the files put in the list of recursive?

martin wrote:

ssAshkea wrote:

And again an error
  No overload for method 'EnumerateRemoteFiles' takes 1 arguments. "[String: 16; Column: 19]

OK, so like this: session.EnumerateRemoteFiles("/home/user/", null, EnumerationOptions.AllDirectories | EnumerationOptions.EnumerateDirectories)

ssAshkea wrote:

And again an error
  No overload for method 'EnumerateRemoteFiles' takes 1 arguments. "[String: 16; Column: 19]

martin wrote:

OK, I've missed that the directory is result of session.ListDirectory is your code.

You have to pass a path as a string to the first argument of session.EnumerateRemoteFiles.

Like: session.EnumerateRemoteFiles("/home/user/")

// Setup session options

SessionOptions sessionOptions = new SessionOptions

{

    Protocol = Protocol.sftp,

    HostName = "server.com",

    UserName = "user",

    Password = "pass",

     SshHostKeyFingerprint = "ssh-rsa 2048 00:00:00:00:00:00:00:00:00:00:00:00:00:00:00:1f"

};



using (Session session = new Session())

{

    

    // Connect

    session.Open(sessionOptions);

   var directory  = session.ListDirectory("/home/user/);

   //var filesCount = session.EnumerateRemoteFiles(directory.ToString(), null, EnumerationOptions.AllDirectories);

   //var directoriesCount = session.EnumerateRemoteFiles(directory.ToString(), null, EnumerationOptions.AllDirectories | EnumerationOptions.EnumerateDirectories).Where(file => file.IsDirectory);

   

   return filesCount.Count()  ;

 

   session.Close();

}

martin wrote:

I do not know what is "kol-in folders", but this may help:

int directoriesCount =

    session.EnumerateRemoteFiles(directory, null, EnumerationOptions.AllDirectories | EnumerationOptions.EnumerateDirectories)

        .Where(file => file.IsDirectory)

        .Count();

Error listing directory 'WinSCP.RemoteDirectoryInfo'.

No such file or directory.

Error code: 2

Error message from server: No such file

martin wrote:

I do not know what is "kol-in folders", but this may help:

int directoriesCount =

    session.EnumerateRemoteFiles(directory, null, EnumerationOptions.AllDirectories | EnumerationOptions.EnumerateDirectories)

        .Where(file => file.IsDirectory)

        .Count();