The new version resolves the problem. Thanks.
- floppymaster
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Topic review
- martin
Re: Session code generator for PowerShell outputs un-escaped dollar signs in double quoted literals
This bug has been added to the tracker:
https://winscp.net/tracker/1590
I'm sending you an email with a development version of WinSCP to the address you have used to register on this forum.
https://winscp.net/tracker/1590
I'm sending you an email with a development version of WinSCP to the address you have used to register on this forum.
- martin
Re: Session code generator for PowerShell outputs un-escaped dollar signs in double quoted literals
Thanks. Will look into this.
- floppymaster
Alternatively, the dollar sign may be escaped using a backtick (`) character. Backticks also need to be escaped.
pa$w"or`d -> "pa`$w`"or``d"
- floppymaster
Session code generator for PowerShell outputs un-escaped dollar signs in double quoted literals
The Powershell code generator encapsulates string literals in double quotes. If any of the values contain a dollar sign, Powershell will interpret this as a variable reference.
For example:
An easy solution would be to use single quotes instead.
For example:
# Set up session options
$sessionOptions = New-Object WinSCP.SessionOptions -Property @{
Protocol = [WinSCP.Protocol]::Sftp
HostName = "ftp.example.com"
UserName = "myuser"
Password = "pa$sword" # Accidental reference to '$sword' variable
SshHostKeyFingerprint = "ssh-rsa 2048 0b:1e:4b:29:43:7e:a3:aa:f4:6b:fe:50:cb:32:f8:35"
}
An easy solution would be to use single quotes instead.
# Set up session options
$sessionOptions = New-Object WinSCP.SessionOptions -Property @{
Protocol = [WinSCP.Protocol]::Sftp
HostName = 'ftp.example.com'
UserName = 'myuser'
Password = 'pa$sword'
SshHostKeyFingerprint = 'ssh-rsa 2048 0b:1e:4b:29:43:7e:a3:aa:f4:6b:fe:50:cb:32:f8:35'
}