this %28%26%2a password was present in my batch script.
can you please let me know how to know original password

(&*
See https://en.wikipedia.org/wiki/ASCII#ASCII-printable-characters

this %28%26%2a password was present in my batch script.
can you please let me know how to know original password

It's only guess, as the log file is not complete: In Windows batch file the % sign has a special meaning. Particularly the %2 is replaced with the second argument of the batch file. So the %2 never makes it to WinSCP. You need to escape the % by doubling it to %%2B9lz3-MN.

See https://winscp.net/eng/docs/faq_batch_file#percent

Hello
I cant connect to a sftp through a bat file
apparently the password does not get recognized because it has some special characters

original password: +9lz3-MN
encoded password: %2B9lz3-MN

Batch File contains the following:
"C:\Program Files (x86)\WinSCP\WinSCP.com" /log="C:\WinSCP.log" /ini=nul /command "option batch continue" "option confirm off" "open sftp://<username>:%2B9lz3-MN/ -hostkey=""ssh-rsa 2048 xxx""" "option transfer binary" "synchronize local C:\ /Info/" "exit"

I'm getting the following log errors: