Count and list total files per folder at remote site
I know this has been asked before and I have searched online and read some of the related articles here on the forum for counting files. I have tried most of them and end with some error or the other. The most common error is
I tried different iterations of the script and this one gets me a file count, but not in the format that I want. The output comes out like this – and count is correct.
I would like to get an output in this format:
and so on. (if that is not possible, then the total count of all files is enough)
Thank you for your input.
Here is the script that I tried, which gave the above output:
I saw another article where this error was brought up and Martin addressed it, but I could not quite make out what he was asking to implement and the person who asked the question, did not comment on that final help provided :(Cannot Find an overload for EnumerateRemoteFiles and the argument count: "2"
I tried different iterations of the script and this one gets me a file count, but not in the format that I want. The output comes out like this – and count is correct.
Number of files in /Test/ is 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
Test/ABC 2 Test/XVZ 6
Thank you for your input.
Here is the script that I tried, which gave the above output:
#Load WinSCP assembly Add-Type -Path "C:\Program Files (x86)\WinSCP\WinSCPnet.dll" # Session settings $sessionOptions = New-Object WinSCP.SessionOptions -property{ # all the usual stuff } # Create session and connect $session = New-Object WinSCP.Session $session.Open($sessionOptions) # Remote directory to count files in $remoteDirectory = "/Test/" # Enumerate files and count them recursively $fileCount = $session.EnumerateRemoteFiles( $remoteDirectory, "*.*", [WinSCP.EnumerationOptions]::AllDirectories).Count # Close session $session.Dispose() # Output the count Write-Host "Number of files in $remoteDirectory is $fileCount"
