SOLVED - Check if any file exist and return a value - Powershell

Muffinz wrote:

Hi,

How can I check if any file exist on a remote FTP-server with powershell and so the return value is False or True?
I need that value since I use Invoke-Command in an other script to call for this script and if it isn't possible I can change the script a bit so it write to a logfile and I'll have another script checking that log file.

See the "# Check File" line

This returns the value False even if there is a file on the remote location:

    # Connect
    $session.Open($sessionOptions)
   

    # Remote Path
    $remotePath = "/transfer/ut/*" 
    
    # Check File
    $Exsist = $session.FileExists($remotePath)
      
    # Disconnect, clean up 
    $session.Dispose()

And this return me with the filename/filenames looking like this:

Files            
-----            
{.., file.txt, .}

or

Files            
-----            
{.., ., file.txt}

or

Files  
-----  
{.., .}

   
    # Connect
    $session.Open($sessionOptions)
   

    # Remote Path
    $remotePath = "/transfer/ut/" 
    
    # Check File
    $Exsist = $session.ListDirectory($remotePath)
      
    # Disconnect, clean up 
    $session.Dispose()

Thank you!

savoym wrote:

You might try something like this:

if ($session.FileExists($remoteFile1)) {
Write-Output true |
Out-File -Append "C:\testTrue.txt"
} else {
Write-Output false |
Out-File -Append "C:\testFalse.txt"
}

Muffinz wrote:

savoym wrote:

You might try something like this:

if ($session.FileExists($remoteFile1)) {
Write-Output true |
Out-File -Append "C:\testTrue.txt"
} else {
Write-Output false |
Out-File -Append "C:\testFalse.txt"
}

Hi,

Thank you for the reply :)

The problem is when I use ".FileExists" I seems to be needed to specify a filename and I can't do that since all the files have different filenames.

Please correct me if I'm wrong or if I misunderstood something.

martin wrote:

Something like [Linq.Enumerable]::Any($session.EnumerateRemoteFiles("/transfer/ut", $Null, [WinSCP.EnumerationOptions]::None))

$Contents = $session.EnumerateRemoteFiles($remotePath, "*.*",[WinSCP.EnumerationOptions]::AllDirectories)
$Contents | select Name | Out-File