$WinSCPPath = ".\deployment\tools\WinSCP"; & "$WinSCPPath\WinSCP" /ini="$WinSCPPath\config.ini" /command ` "open scp://USER@HOST:PORT -privatekey=""./deployment/keys/scp_id.ppk"" -passphrase=""PASS PHRASE""" ` "rm build_drop/*" ` "put releases/current/*.7z" ` "exit";
When this runs, everything appears to work down to the "put" line where I get the error:
File or folder 'pack_20190104085125.7z' does not exist. System Error. Code: 2. The system cannot find the file specified (A)bort, (R)etry, (S)kip, Ski(p) all:
The reason why I'm confused is, that 'pack_20190104085125.7z' DOES exist and I did not hardcode it anywhere in the script so it means that WinSCP was able to read the filename. Why does it declare that the file does not exist?