TLS connection error/bug

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robbone
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2

TLS connection error/bug

I'm trying to do a TLS connection using .NET library in C#, but I'm receivin a SSH error, it seems a bug.

Here my code:
SessionOptions sessionOptions = new SessionOptions();
                sessionOptions.HostName = _hostName;
                sessionOptions.Password = _password;
                sessionOptions.UserName = _userName;
                sessionOptions.Protocol = Protocol.Ftp;
                sessionOptions.FtpSecure = FtpSecure.Implicit;
                sessionOptions.PortNumber = 990;
                sessionOptions.FtpMode = FtpMode.Passive;    

If I set:
sessionOptions.GiveUpSecurityAndAcceptAnyTlsHostCertificate = true;    

I get the error:
System.ArgumentException: SessionOptions.SshHostKey or SessionOptions.GiveUpSecurityAndAcceptAnySshHostKey is set, but SessionOptions.Protocol is not Protocol.Sftp nor Protocol.Scp.    

If I set:
sessionOptions.GiveUpSecurityAndAcceptAnySshHostKey    

I get the same error above.

If I set:
sessionOptions.TlsHostCertificateFingerprint = "61:79:71...";    

I get teh same error above, again

If I set
sessionOptions.SshHostKeyFingerprint = "61:79:71..."    

I get the error:
System.ArgumentException: SSH host key fingerprint "61:79:71..." does not match pattern /((ssh-rsa|ssh-dss)( |-))?(\d+ )?([0-9a-f]{2}(:|-)){15}[0-9a-f]{2}(;((ssh-rsa|ssh-dss)( |-))?(\d+ )?([0-9a-f]{2}(:|-)){15}[0-9a-f]{2})*/    

When I set TLS properties, the error says that I'm using SSH properties. So I believe it is a bug.

Can anyone help me?

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Re: TLS connection error/bug

I tested with versions 5.7.0 and 5.7.2

robbone wrote:

I'm trying to do a TLS connection using .NET library in C#, but I'm receivin a SSH error, it seems a bug.

Here my code:
SessionOptions sessionOptions = new SessionOptions();
                sessionOptions.HostName = _hostName;
                sessionOptions.Password = _password;
                sessionOptions.UserName = _userName;
                sessionOptions.Protocol = Protocol.Ftp;
                sessionOptions.FtpSecure = FtpSecure.Implicit;
                sessionOptions.PortNumber = 990;
                sessionOptions.FtpMode = FtpMode.Passive;    

If I set:
sessionOptions.GiveUpSecurityAndAcceptAnyTlsHostCertificate = true;    

I get the error:
System.ArgumentException: SessionOptions.SshHostKey or SessionOptions.GiveUpSecurityAndAcceptAnySshHostKey is set, but SessionOptions.Protocol is not Protocol.Sftp nor Protocol.Scp.    

If I set:
sessionOptions.GiveUpSecurityAndAcceptAnySshHostKey    

I get the same error above.

If I set:
sessionOptions.TlsHostCertificateFingerprint = "61:79:71...";    

I get teh same error above, again

If I set
sessionOptions.SshHostKeyFingerprint = "61:79:71..."    

I get the error:
System.ArgumentException: SSH host key fingerprint "61:79:71..." does not match pattern /((ssh-rsa|ssh-dss)( |-))?(\d+ )?([0-9a-f]{2}(:|-)){15}[0-9a-f]{2}(;((ssh-rsa|ssh-dss)( |-))?(\d+ )?([0-9a-f]{2}(:|-)){15}[0-9a-f]{2})*/    

When I set TLS properties, the error says that I'm using SSH properties. So I believe it is a bug.

Can anyone help me?

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martin
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martin avatar
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Location:
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Re: TLS connection error/bug

With this code, I'm not getting any exception:

SessionOptions sessionOptions = new SessionOptions();
sessionOptions.HostName = "localhost";
sessionOptions.Password = "test";
sessionOptions.UserName = "test";
sessionOptions.Protocol = Protocol.Ftp;
sessionOptions.FtpSecure = FtpSecure.Implicit;
sessionOptions.PortNumber = 990;
sessionOptions.FtpMode = FtpMode.Passive;
sessionOptions.GiveUpSecurityAndAcceptAnyTlsHostCertificate = true;

using (Session session = CreateSession())
{
    session.Open(sessionOptions);
}    

Neither with this code:

SessionOptions sessionOptions = new SessionOptions();
sessionOptions.HostName = "localhost";
sessionOptions.Password = "test";
sessionOptions.UserName = "test";
sessionOptions.Protocol = Protocol.Ftp;
sessionOptions.FtpSecure = FtpSecure.Implicit;
sessionOptions.PortNumber = 990;
sessionOptions.FtpMode = FtpMode.Passive;
sessionOptions.TlsHostCertificateFingerprint = "a0:cd:69:37:d2:f6:d3:ee:a7:5d:39:3d:e7:5e:36:f4:9a:83:45:60";

using (Session session = CreateSession())
{
    session.Open(sessionOptions);
}    

Both with 5.7.2.

Please show us your exact complete code that produces the exception.
_________________
Martin Prikryl

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